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How to use an action control, control type: Link, to go to a web url

Caleb.McBride McBride

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Decription: I am working on designing a home page in Spotfire where the user can click action control items within a text area to go to different websites. I know how to do this with an action control, control type: Button as shown in thisTibco community post. I would like to use a action control, control type: Linkso I can apply a style it. Using an action control link, the text appears as a link but does not open anything.

Question: How can I either restyle the button using an edit to the javascript below or correctly use the link button to send to a link


Current Work


HTML code within a text area to make a button that goes to the web. Attached images show visual explanation of what I have and what I am trying to do.





Here, the button is attached to an empty ironpython script.


I am applying styles to the link by using the JS:

// Set up buttons using their class name and build their styling.

// I use % widths so they flex with the text area

$(".myButtons").button().css({ 'width': '10%',

'padding-top': '3px',

'padding-bottom': '3px',

'font-size': '16px',




'font-family': 'Century Gothic, sans-serif' });



I know how to do do this with simple text:https://community.spotfire.com/questions/hyperlink-external-site

I know how to do this in a data table:https://www.tibco.com/resources/product-demonstration-video/how-make-clickable-links-spotfire-table

Java script styling adapted from here:https://community.spotfire.com/questions/tip-how-style-your-action-buttons

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  • 4 weeks later...

You can use action control button itself, just modify some styles for action control button in css as below:


#myButtons {

width: 10%;

padding-top: 3px;

padding-bottom: 3px;

font-size: 16px;




font-family: Century Gothic, sans-serif



#myButtons .sfc-action-button {

background: none;

border-style: none;










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