How can I set an interactive layer on a mapchart in a python script

[Luca de Falco 4]

Hi,How can I set an interactive layer on a mapchart in a python scriptI use this code:

#lay is my layerlay.Enabled="True"

I disable the other layers withlay.Enabled=""It set the layer as visible and as interactive.In a map visualization with 2 layers it works,in an other fail.The layer I want to set is visible,but is not the interactive layer.The interactive layer become the world country layer that I use for geocoding.I hope the problem is clear.

[Manoj Chaurasia]

Ok thanks, my API documentation was deprecated, thanks to you I have found the updated one.

[Manoj Chaurasia]

Hi luca, could you please write your code here

I really apreciate it.

Thanks in advance!!

[Manoj Chaurasia]

What was your final code

[Nicolas Stefaniuk]

Hello. No error It's just that the interactive layer is not the good one Thanks

[Nicolas Stefaniuk]

I didn't find the attribut "Enabled" in API documentation. Have you written your code from an example In fact I think they have forgotten to add a method or an attribute for in the API for Interactive Layers, because it has been rebuild in 6.5

[Luca de Falco 4]

I solved.

I have to set the property : InteractiveLayerReference

[Luca de Falco 4]

Yes,the problems was that the interactive layer was not the good one

[Luca de Falco 4]

Enabled is a mapchartlayer property

[Nicolas Stefaniuk]

Good job, this property is not referenced in the API. How did you find it Thanks

[Luca de Falco 4]

Is referenced in the 6.5 API

Enabled is a MapChartDataLayer property

InteractiveLayerReferencevis a MapChart property

[Luca de Falco 4]

from Spotfire.Dxp.Application.Visuals import VisualTypeIdentifiers

from Spotfire.Dxp.Application.Visuals import MapChart,CategoricalAxis,ScaleAxis

from Spotfire.Dxp.Application.Visuals import VisualContent

from Spotfire.Dxp.Application.Visuals.Maps import MapChart

from Spotfire.Dxp.Application.Visuals import PositioningMethod, MarkerShape, MarkerType

#The script set a layer as visible and interactive if the right value is selected in the dropdown

#v is a parameter

map=v.As[MapChart]()

#layer 1,dropdown value A

#layer 2,dropdownvalue value B

#dropdownvalue is a parameter

if(dropdownvalue=="A"):

lay=map.Layers.Item[1]

lay.Enabled="True"

map.InteractiveLayerReference=lay=map.Layers.Item[1]

lay=map.Layers.Item[2]

lay.Enabled=""

if(dropdownvalue=="B"):

lay=map.Layers.Item[1]

lay.Enabled=""

lay=map.Layers.Item[2]

lay.Enabled="True"

map.InteractiveLayerReference=lay=map.Layers.Item[2]

[Luca de Falco 4]

@[user:50870|Ade Eka]

a bit late :)

[Hector Martinez 2]

You can use this...

from Spotfire.Dxp.Application.Visuals.Maps import MapChart

mychart = map.As[MapChart]()

for layer in mychart.Layers: # loop through all existing layers

if layer.Title=='BOTTOM HOLES': # to find the one you want

mychart.InteractiveLayerReference = layer'

[Charitha Amaraneni]

Hi LucadF,

 

could you please help me in understanding how you did it

 

Thanks,

C